y-2(3+1)=4(y-1)

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Solution for y-2(3+1)=4(y-1) equation:



y-2(3+1)=4(y-1)
We move all terms to the left:
y-2(3+1)-(4(y-1))=0
We add all the numbers together, and all the variables
y-(4(y-1))-24=0
We calculate terms in parentheses: -(4(y-1)), so:
4(y-1)
We multiply parentheses
4y-4
Back to the equation:
-(4y-4)
We get rid of parentheses
y-4y+4-24=0
We add all the numbers together, and all the variables
-3y-20=0
We move all terms containing y to the left, all other terms to the right
-3y=20
y=20/-3
y=-6+2/3

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