y-2(3+1)=4(y-1)

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Solution for y-2(3+1)=4(y-1) equation: 



y-2(3+1)=4(y-1)

We move all terms to the left:

y-2(3+1)-(4(y-1))=0

We add all the numbers together, and all the variables

y-(4(y-1))-24=0



We calculate terms in parentheses: -(4(y-1)), so:

4(y-1)

We multiply parentheses

4y-4

Back to the equation:

-(4y-4)



We get rid of parentheses

y-4y+4-24=0

We add all the numbers together, and all the variables

-3y-20=0

We move all terms containing y to the left, all other terms to the right

-3y=20

y=20/-3

y=-6+2/3

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