y-2(6-y)=3(y-4)

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Solution for y-2(6-y)=3(y-4) equation: 



y-2(6-y)=3(y-4)

We move all terms to the left:

y-2(6-y)-(3(y-4))=0

We add all the numbers together, and all the variables

y-2(-1y+6)-(3(y-4))=0

We multiply parentheses

y+2y-(3(y-4))-12=0



We calculate terms in parentheses: -(3(y-4)), so:

3(y-4)

We multiply parentheses

3y-12

Back to the equation:

-(3y-12)



We add all the numbers together, and all the variables

3y-(3y-12)-12=0

We get rid of parentheses

3y-3y+12-12=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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