y-2+4(3y+1)=-3(y+4)

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Solution for y-2+4(3y+1)=-3(y+4) equation: 



y-2+4(3y+1)=-3(y+4)

We move all terms to the left:

y-2+4(3y+1)-(-3(y+4))=0

We multiply parentheses

y+12y-(-3(y+4))+4-2=0



We calculate terms in parentheses: -(-3(y+4)), so:

-3(y+4)

We multiply parentheses

-3y-12

Back to the equation:

-(-3y-12)



We add all the numbers together, and all the variables

13y-(-3y-12)+2=0

We get rid of parentheses

13y+3y+12+2=0

We add all the numbers together, and all the variables

16y+14=0

We move all terms containing y to the left, all other terms to the right

16y=-14

y=-14/16

y=-7/8

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