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y-2/3y=600
We move all terms to the left:
y-2/3y-(600)=0
Domain of the equation: 3y!=0We multiply all the terms by the denominator
y!=0/3
y!=0
y∈R
y*3y-600*3y-2=0
Wy multiply elements
3y^2-1800y-2=0
a = 3; b = -1800; c = -2;
Δ = b2-4ac
Δ = -18002-4·3·(-2)
Δ = 3240024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3240024}=\sqrt{4*810006}=\sqrt{4}*\sqrt{810006}=2\sqrt{810006}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1800)-2\sqrt{810006}}{2*3}=\frac{1800-2\sqrt{810006}}{6} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1800)+2\sqrt{810006}}{2*3}=\frac{1800+2\sqrt{810006}}{6} $
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