y-25y2+144=0

Solution for y-25y2+144=0 equation:

y-25y^2+144=0

a = -25; b = 1; c = +144;
Δ = b2-4ac
Δ = 12-4·(-25)·144
Δ = 14401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{14401}}{2*-25}=\frac{-1-\sqrt{14401}}{-50}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{14401}}{2*-25}=\frac{-1+\sqrt{14401}}{-50}
$