y-3(y+2)=2(y-7)

Solution for y-3(y+2)=2(y-7) equation:

y-3(y+2)=2(y-7)

We move all terms to the left:

y-3(y+2)-(2(y-7))=0

We multiply parentheses

y-3y-(2(y-7))-6=0


We calculate terms in parentheses: -(2(y-7)), so:

2(y-7)

We multiply parentheses

2y-14

Back to the equation:

-(2y-14)


We add all the numbers together, and all the variables

-2y-(2y-14)-6=0

We get rid of parentheses

-2y-2y+14-6=0

We add all the numbers together, and all the variables

-4y+8=0

We move all terms containing y to the left, all other terms to the right

-4y=-8

y=-8/-4

y=+2