y-3/y-2

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Solution for y-3/y-2 equation:


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

y-(3/y)-2 = 0

y-3*y^-1-2 = 0

1*y^1-3*y^-1-2*y^0 = 0

(1*y^2-2*y^1-3*y^0)/(y^1) = 0 // * y^2

y^1*(1*y^2-2*y^1-3*y^0) = 0

y^1

y^2-2*y-3 = 0

y^2-2*y-3 = 0

DELTA = (-2)^2-(-3*1*4)

DELTA = 16

DELTA > 0

y = (16^(1/2)+2)/(1*2) or y = (2-16^(1/2))/(1*2)

y = 3 or y = -1

y in { -1, 3}

y in { -1, 3 }

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