y-5+2(2y+2)=-4(y+4)

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Solution for y-5+2(2y+2)=-4(y+4) equation: 



y-5+2(2y+2)=-4(y+4)

We move all terms to the left:

y-5+2(2y+2)-(-4(y+4))=0

We multiply parentheses

y+4y-(-4(y+4))+4-5=0



We calculate terms in parentheses: -(-4(y+4)), so:

-4(y+4)

We multiply parentheses

-4y-16

Back to the equation:

-(-4y-16)



We add all the numbers together, and all the variables

5y-(-4y-16)-1=0

We get rid of parentheses

5y+4y+16-1=0

We add all the numbers together, and all the variables

9y+15=0

We move all terms containing y to the left, all other terms to the right

9y=-15

y=-15/9

y=-1+2/3

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