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y-5/8y=3
We move all terms to the left:
y-5/8y-(3)=0
Domain of the equation: 8y!=0We multiply all the terms by the denominator
y!=0/8
y!=0
y∈R
y*8y-3*8y-5=0
Wy multiply elements
8y^2-24y-5=0
a = 8; b = -24; c = -5;
Δ = b2-4ac
Δ = -242-4·8·(-5)
Δ = 736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{736}=\sqrt{16*46}=\sqrt{16}*\sqrt{46}=4\sqrt{46}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-4\sqrt{46}}{2*8}=\frac{24-4\sqrt{46}}{16} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+4\sqrt{46}}{2*8}=\frac{24+4\sqrt{46}}{16} $
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