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y-8/9y=11
We move all terms to the left:
y-8/9y-(11)=0
Domain of the equation: 9y!=0We multiply all the terms by the denominator
y!=0/9
y!=0
y∈R
y*9y-11*9y-8=0
Wy multiply elements
9y^2-99y-8=0
a = 9; b = -99; c = -8;
Δ = b2-4ac
Δ = -992-4·9·(-8)
Δ = 10089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{10089}=\sqrt{9*1121}=\sqrt{9}*\sqrt{1121}=3\sqrt{1121}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-99)-3\sqrt{1121}}{2*9}=\frac{99-3\sqrt{1121}}{18} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-99)+3\sqrt{1121}}{2*9}=\frac{99+3\sqrt{1121}}{18} $
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