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y/3+(3y/4y)=9/2(y-1
We move all terms to the left:
y/3+(3y/4y)-(9/2(y-1)=0
Domain of the equation: 4y)!=0
y!=0/1
y!=0
y∈R
Domain of the equation: 2(y-1)!=0We add all the numbers together, and all the variables
y∈R
y/3+(+3y/4y)-(9/2(y-1)=0
We get rid of parentheses
y/3+3y/4y-(9/2(y-1)=0
We calculate fractions
We do not support eypression: y^3
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