y/3+12=16

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Solution for y/3+12=16 equation: 



y/3+12=16

We move all terms to the left:

y/3+12-(16)=0

We add all the numbers together, and all the variables

y/3-4=0

We multiply all the terms by the denominator


y-4*3=0

We add all the numbers together, and all the variables

y-12=0

We move all terms containing y to the left, all other terms to the right

y=12

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