y/3+12=32

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Solution for y/3+12=32 equation: 



y/3+12=32

We move all terms to the left:

y/3+12-(32)=0

We add all the numbers together, and all the variables

y/3-20=0

We multiply all the terms by the denominator


y-20*3=0

We add all the numbers together, and all the variables

y-60=0

We move all terms containing y to the left, all other terms to the right

y=60

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