y/y-2=y+1/y-5

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Solution for y/y-2=y+1/y-5 equation:



y/y-2=y+1/y-5
We move all terms to the left:
y/y-2-(y+1/y-5)=0
Domain of the equation: y!=0
y∈R
Domain of the equation: y-5)!=0
y∈R
We get rid of parentheses
y/y-y-1/y+5-2=0
Fractions to decimals
-1/y-y+5-2+1=0
We multiply all the terms by the denominator
-y*y+5*y-2*y+1*y-1=0
We add all the numbers together, and all the variables
4y-y*y-1=0
Wy multiply elements
-1y^2+4y-1=0
a = -1; b = 4; c = -1;
Δ = b2-4ac
Δ = 42-4·(-1)·(-1)
Δ = 12
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{12}=\sqrt{4*3}=\sqrt{4}*\sqrt{3}=2\sqrt{3}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{3}}{2*-1}=\frac{-4-2\sqrt{3}}{-2} $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{3}}{2*-1}=\frac{-4+2\sqrt{3}}{-2} $

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