y1-y2+y1=10y2=-4

Solution for y1-y2+y1=10y2=-4 equation:

y1-y2+y1=10y^2=-4

We move all terms to the left:

y1-y2+y1-(10y^2)=0

determiningTheFunctionDomain
-10y^2+y1-y2+y1=0

We add all the numbers together, and all the variables

-11y^2+2y=0

a = -11; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-11)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-11}=\frac{-4}{-22}
=2/11
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-11}=\frac{0}{-22}
=0
$