y2+0.9955y-0.00903=0

Solution for y2+0.9955y-0.00903=0 equation:

y2+0.9955y-0.00903=0

We add all the numbers together, and all the variables

y^2+0.9955y-0.00903=0

a = 1; b = 0.9955; c = -0.00903;
Δ = b2-4ac
Δ = 0.99552-4·1·(-0.00903)
Δ = 1.02714025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.9955)-\sqrt{1.02714025}}{2*1}=\frac{-0.9955-\sqrt{1.02714025}}{2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.9955)+\sqrt{1.02714025}}{2*1}=\frac{-0.9955+\sqrt{1.02714025}}{2}
$