y2+1.0515y-0.5893=0

Solution for y2+1.0515y-0.5893=0 equation:

y2+1.0515y-0.5893=0

We add all the numbers together, and all the variables

y^2+1.0515y-0.5893=0

a = 1; b = 1.0515; c = -0.5893;
Δ = b2-4ac
Δ = 1.05152-4·1·(-0.5893)
Δ = 3.46285225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.0515)-\sqrt{3.46285225}}{2*1}=\frac{-1.0515-\sqrt{3.46285225}}{2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.0515)+\sqrt{3.46285225}}{2*1}=\frac{-1.0515+\sqrt{3.46285225}}{2}
$