y2+1.141y-0.7589=0

Solution for y2+1.141y-0.7589=0 equation:

y2+1.141y-0.7589=0

We add all the numbers together, and all the variables

y^2+1.141y-0.7589=0

a = 1; b = 1.141; c = -0.7589;
Δ = b2-4ac
Δ = 1.1412-4·1·(-0.7589)
Δ = 4.337481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.141)-\sqrt{4.337481}}{2*1}=\frac{-1.141-\sqrt{4.337481}}{2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.141)+\sqrt{4.337481}}{2*1}=\frac{-1.141+\sqrt{4.337481}}{2}
$