y2+11y-72=2y-3

Solution for y2+11y-72=2y-3 equation:

y2+11y-72=2y-3

We move all terms to the left:

y2+11y-72-(2y-3)=0

We add all the numbers together, and all the variables

y^2+11y-(2y-3)-72=0

We get rid of parentheses

y^2+11y-2y+3-72=0

We add all the numbers together, and all the variables

y^2+9y-69=0

a = 1; b = 9; c = -69;
Δ = b2-4ac
Δ = 92-4·1·(-69)
Δ = 357
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{357}}{2*1}=\frac{-9-\sqrt{357}}{2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{357}}{2*1}=\frac{-9+\sqrt{357}}{2}
$