y2+12=(y+2)2

Solution for y2+12=(y+2)2 equation:

y2+12=(y+2)2

We move all terms to the left:

y2+12-((y+2)2)=0

We add all the numbers together, and all the variables

y^2-((y+2)2)+12=0


We calculate terms in parentheses: -((y+2)2), so:

(y+2)2

We multiply parentheses

2y+4

Back to the equation:

-(2y+4)


We get rid of parentheses

y^2-2y-4+12=0

We add all the numbers together, and all the variables

y^2-2y+8=0

a = 1; b = -2; c = +8;
Δ = b2-4ac
Δ = -22-4·1·8
Δ = -28
Delta is less than zero, so there is no solution for the equation