y2+12y+36=0.

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Solution for y2+12y+36=0. equation:



y2+12y+36=0.
We add all the numbers together, and all the variables
y^2+12y+36=0
a = 1; b = 12; c = +36;
Δ = b2-4ac
Δ = 122-4·1·36
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{-12}{2}=-6$

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