y2+12y-200=0

Solution for y2+12y-200=0 equation:

y2+12y-200=0

We add all the numbers together, and all the variables

y^2+12y-200=0

a = 1; b = 12; c = -200;
Δ = b2-4ac
Δ = 122-4·1·(-200)
Δ = 944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{944}=\sqrt{16*59}=\sqrt{16}*\sqrt{59}=4\sqrt{59}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-4\sqrt{59}}{2*1}=\frac{-12-4\sqrt{59}}{2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+4\sqrt{59}}{2*1}=\frac{-12+4\sqrt{59}}{2}
$