y2+17y-480=0

Solution for y2+17y-480=0 equation:

y2+17y-480=0

We add all the numbers together, and all the variables

y^2+17y-480=0

a = 1; b = 17; c = -480;
Δ = b2-4ac
Δ = 172-4·1·(-480)
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2209}=47$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-47}{2*1}=\frac{-64}{2}
=-32
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+47}{2*1}=\frac{30}{2}
=15
$