y2+18y+65=(y+13)(y+)

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Solution for y2+18y+65=(y+13)(y+) equation: 



y2+18y+65=(y+13)(y+)

We move all terms to the left:

y2+18y+65-((y+13)(y+))=0

We add all the numbers together, and all the variables

y2+18y-((y+13)(+y))+65=0

We add all the numbers together, and all the variables

y^2+18y-((y+13)(+y))+65=0

We multiply parentheses ..

y^2-((+y^2+13y))+18y+65=0



We calculate terms in parentheses: -((+y^2+13y)), so:

(+y^2+13y)

We get rid of parentheses

y^2+13y

Back to the equation:

-(y^2+13y)



We add all the numbers together, and all the variables

y^2+18y-(y^2+13y)+65=0

We get rid of parentheses

y^2-y^2+18y-13y+65=0

We add all the numbers together, and all the variables

5y+65=0

We move all terms containing y to the left, all other terms to the right

5y=-65

y=-65/5

y=-13

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