y2+37y+340=0

Solution for y2+37y+340=0 equation:

y2+37y+340=0

We add all the numbers together, and all the variables

y^2+37y+340=0

a = 1; b = 37; c = +340;
Δ = b2-4ac
Δ = 372-4·1·340
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-3}{2*1}=\frac{-40}{2}
=-20
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+3}{2*1}=\frac{-34}{2}
=-17
$