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y2+4=3
We move all terms to the left:
y2+4-(3)=0
We add all the numbers together, and all the variables
y^2+1=0
a = 1; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·1·1
Δ = -4
Delta is less than zero, so there is no solution for the equation
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