y2+53=4y

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Solution for y2+53=4y equation: 



y2+53=4y

We move all terms to the left:

y2+53-(4y)=0

We add all the numbers together, and all the variables

y^2-4y+53=0

a = 1; b = -4; c = +53;
Δ = b2-4ac
Δ = -42-4·1·53
Δ = -196
Delta is less than zero, so there is no solution for the equation

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