y2+9y=8

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Solution for y2+9y=8 equation:



y2+9y=8
We move all terms to the left:
y2+9y-(8)=0
We add all the numbers together, and all the variables
y^2+9y-8=0
a = 1; b = 9; c = -8;
Δ = b2-4ac
Δ = 92-4·1·(-8)
Δ = 113
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{113}}{2*1}=\frac{-9-\sqrt{113}}{2} $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{113}}{2*1}=\frac{-9+\sqrt{113}}{2} $

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