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y2-10y=9
We move all terms to the left:
y2-10y-(9)=0
We add all the numbers together, and all the variables
y^2-10y-9=0
a = 1; b = -10; c = -9;
Δ = b2-4ac
Δ = -102-4·1·(-9)
Δ = 136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{136}=\sqrt{4*34}=\sqrt{4}*\sqrt{34}=2\sqrt{34}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{34}}{2*1}=\frac{10-2\sqrt{34}}{2} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{34}}{2*1}=\frac{10+2\sqrt{34}}{2} $
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