y2-12y=-36

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Solution for y2-12y=-36 equation: 



y2-12y=-36

We move all terms to the left:

y2-12y-(-36)=0

We add all the numbers together, and all the variables

y^2-12y+36=0

a = 1; b = -12; c = +36;
Δ = b2-4ac
Δ = -122-4·1·36
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{12}{2}=6$

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