y2-29y+100=0

Solution for y2-29y+100=0 equation:

y2-29y+100=0

We add all the numbers together, and all the variables

y^2-29y+100=0

a = 1; b = -29; c = +100;
Δ = b2-4ac
Δ = -292-4·1·100
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-21}{2*1}=\frac{8}{2}
=4
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+21}{2*1}=\frac{50}{2}
=25
$