y2-39y+338=0

Solution for y2-39y+338=0 equation:

y2-39y+338=0

We add all the numbers together, and all the variables

y^2-39y+338=0

a = 1; b = -39; c = +338;
Δ = b2-4ac
Δ = -392-4·1·338
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-39)-13}{2*1}=\frac{26}{2}
=13
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-39)+13}{2*1}=\frac{52}{2}
=26
$