y2-545y+14000=0

Solution for y2-545y+14000=0 equation:

y2-545y+14000=0

We add all the numbers together, and all the variables

y^2-545y+14000=0

a = 1; b = -545; c = +14000;
Δ = b2-4ac
Δ = -5452-4·1·14000
Δ = 241025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{241025}=\sqrt{25*9641}=\sqrt{25}*\sqrt{9641}=5\sqrt{9641}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-545)-5\sqrt{9641}}{2*1}=\frac{545-5\sqrt{9641}}{2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-545)+5\sqrt{9641}}{2*1}=\frac{545+5\sqrt{9641}}{2}
$