If it's not what You are looking for type in the equation solver your own equation and let us solve it.
y2-8y=7
We move all terms to the left:
y2-8y-(7)=0
We add all the numbers together, and all the variables
y^2-8y-7=0
a = 1; b = -8; c = -7;
Δ = b2-4ac
Δ = -82-4·1·(-7)
Δ = 92
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{92}=\sqrt{4*23}=\sqrt{4}*\sqrt{23}=2\sqrt{23}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-2\sqrt{23}}{2*1}=\frac{8-2\sqrt{23}}{2} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+2\sqrt{23}}{2*1}=\frac{8+2\sqrt{23}}{2} $
| 4-2z3=34-5z6 | | 10-10x10+10=Y | | 5g+3.53=27.88 | | 27.88=5g+3.53 | | 8x-4+6x+8+1=180 | | 16+5n=−7(−6+8n)+3 | | x+(x-30)°=180° | | 12x+30+8x–6=10 | | Y²/4+2=y | | 2x+2-3.2x=16 | | 5×-4y=31 | | 2^(2x+3)=3^(x-13) | | 33+7y=5(6y+3)5 | | Y=3/5+5u | | -5(y+7)=-10 | | 3x+4=-34-2 | | X+x-7+x+4=300 | | (36-12)×11x=99 | | X2+x+30=0 | | F(2)=~2x+3 | | 0.5×x^2=7 | | x+4/3=x+2 | | 5x+4/6=1x-2/6 | | x/4+2×=18 | | 12x-5=-4x+15 | | 6x-16x=5x-9 | | b÷12=10÷15 | | x=2^0.25 | | 3/2(9-5y)+2y=8 | | 13w-13=3w+12 | | m²+2m-8=0 | | -9=-5x-2(4x+37) |