y2=1.96

Solution for y2=1.96 equation:

y2=1.96

We move all terms to the left:

y2-(1.96)=0

We add all the numbers together, and all the variables

y^2-1.96=0

a = 1; b = 0; c = -1.96;
Δ = b2-4ac
Δ = 02-4·1·(-1.96)
Δ = 7.84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{7.84}}{2*1}=\frac{0-\sqrt{7.84}}{2}
=-\frac{\sqrt{}}{2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{7.84}}{2*1}=\frac{0+\sqrt{7.84}}{2}
=\frac{\sqrt{}}{2}
$