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y2=1130
We move all terms to the left:
y2-(1130)=0
We add all the numbers together, and all the variables
y^2-1130=0
a = 1; b = 0; c = -1130;
Δ = b2-4ac
Δ = 02-4·1·(-1130)
Δ = 4520
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4520}=\sqrt{4*1130}=\sqrt{4}*\sqrt{1130}=2\sqrt{1130}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{1130}}{2*1}=\frac{0-2\sqrt{1130}}{2} =-\frac{2\sqrt{1130}}{2} =-\sqrt{1130} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{1130}}{2*1}=\frac{0+2\sqrt{1130}}{2} =\frac{2\sqrt{1130}}{2} =\sqrt{1130} $
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