y2=1130

Solution for y2=1130 equation:

y2=1130

We move all terms to the left:

y2-(1130)=0

We add all the numbers together, and all the variables

y^2-1130=0

a = 1; b = 0; c = -1130;
Δ = b2-4ac
Δ = 02-4·1·(-1130)
Δ = 4520
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4520}=\sqrt{4*1130}=\sqrt{4}*\sqrt{1130}=2\sqrt{1130}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{1130}}{2*1}=\frac{0-2\sqrt{1130}}{2}
=-\frac{2\sqrt{1130}}{2}
=-\sqrt{1130}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{1130}}{2*1}=\frac{0+2\sqrt{1130}}{2}
=\frac{2\sqrt{1130}}{2}
=\sqrt{1130}
$