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y2=12y-36
We move all terms to the left:
y2-(12y-36)=0
We add all the numbers together, and all the variables
y^2-(12y-36)=0
We get rid of parentheses
y^2-12y+36=0
a = 1; b = -12; c = +36;
Δ = b2-4ac
Δ = -122-4·1·36
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$y=\frac{-b}{2a}=\frac{12}{2}=6$
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