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y2=192
We move all terms to the left:
y2-(192)=0
We add all the numbers together, and all the variables
y^2-192=0
a = 1; b = 0; c = -192;
Δ = b2-4ac
Δ = 02-4·1·(-192)
Δ = 768
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{768}=\sqrt{256*3}=\sqrt{256}*\sqrt{3}=16\sqrt{3}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{3}}{2*1}=\frac{0-16\sqrt{3}}{2} =-\frac{16\sqrt{3}}{2} =-8\sqrt{3} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{3}}{2*1}=\frac{0+16\sqrt{3}}{2} =\frac{16\sqrt{3}}{2} =8\sqrt{3} $
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