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y2=22/49
We move all terms to the left:
y2-(22/49)=0
We add all the numbers together, and all the variables
y2-(+22/49)=0
We add all the numbers together, and all the variables
y^2-(+22/49)=0
We get rid of parentheses
y^2-22/49=0
We multiply all the terms by the denominator
y^2*49-22=0
Wy multiply elements
49y^2-22=0
a = 49; b = 0; c = -22;
Δ = b2-4ac
Δ = 02-4·49·(-22)
Δ = 4312
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4312}=\sqrt{196*22}=\sqrt{196}*\sqrt{22}=14\sqrt{22}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14\sqrt{22}}{2*49}=\frac{0-14\sqrt{22}}{98} =-\frac{14\sqrt{22}}{98} =-\frac{\sqrt{22}}{7} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14\sqrt{22}}{2*49}=\frac{0+14\sqrt{22}}{98} =\frac{14\sqrt{22}}{98} =\frac{\sqrt{22}}{7} $
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