y2=3.2

Solution for y2=3.2 equation:

y2=3.2

We move all terms to the left:

y2-(3.2)=0

We add all the numbers together, and all the variables

y^2-3.2=0

a = 1; b = 0; c = -3.2;
Δ = b2-4ac
Δ = 02-4·1·(-3.2)
Δ = 12.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{12.8}}{2*1}=\frac{0-\sqrt{12.8}}{2}
=-\frac{\sqrt{}}{2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{12.8}}{2*1}=\frac{0+\sqrt{12.8}}{2}
=\frac{\sqrt{}}{2}
$