y2=341

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Solution for y2=341 equation:



y2=341
We move all terms to the left:
y2-(341)=0
We add all the numbers together, and all the variables
y^2-341=0
a = 1; b = 0; c = -341;
Δ = b2-4ac
Δ = 02-4·1·(-341)
Δ = 1364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{1364}=\sqrt{4*341}=\sqrt{4}*\sqrt{341}=2\sqrt{341}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{341}}{2*1}=\frac{0-2\sqrt{341}}{2} =-\frac{2\sqrt{341}}{2} =-\sqrt{341} $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{341}}{2*1}=\frac{0+2\sqrt{341}}{2} =\frac{2\sqrt{341}}{2} =\sqrt{341} $

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