y3(y+)+4=2(y-1+y+y

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Solution for y3(y+)+4=2(y-1+y+y equation: 



y3(y+)+4=2(y-1+y+y

We move all terms to the left:

y3(y+)+4-(2(y-1+y+y)=0

We add all the numbers together, and all the variables

y3(+y)-(2(3y-1)+4=0

We multiply parentheses

y^4-(2(3y-1)+4=0

We do not support eypression: y^4

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