y3/2=y5

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Solution for y3/2=y5 equation: 


y in (-oo:+oo)

(y^3)/2 = y^5 // - y^5

(y^3)/2-y^5 = 0

1/2*y^3-y^5 = 0

y^3*(1/2-y^2) = 0

-1*y^2 = -1/2 // : -1

y^2 = 1/2

y^2 = 1/2 // ^ 1/2

abs(y) = (1/2)^(1/2)

y = (1/2)^(1/2) or y = -(1/2)^(1/2)

y^3 = 0

1*y^3 = 0 // : 1

y^3 = 0

y = 0

y in { (1/2)^(1/2), -(1/2)^(1/2), 0 }

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