y7(y-4)=3(3+y)-1

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Solution for y7(y-4)=3(3+y)-1 equation: 



y7(y-4)=3(3+y)-1

We move all terms to the left:

y7(y-4)-(3(3+y)-1)=0

We add all the numbers together, and all the variables

y7(y-4)-(3(y+3)-1)=0

We multiply parentheses

y^8-4y^7-(3(y+3)-1)=0



We calculate terms in parentheses: -(3(y+3)-1), so:

3(y+3)-1

We multiply parentheses

3y+9-1

We add all the numbers together, and all the variables

3y+8

Back to the equation:

-(3y+8)



We do not support eypression: y^8

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