y=(-15/13)(48)+19440

Solution for y=(-15/13)(48)+19440 equation:

y=(-15/13)(48)+19440

We move all terms to the left:

y-((-15/13)(48)+19440)=0

We multiply all the terms by the denominator


y*13)48+19440)-((-15=0

Wy multiply elements

13y^2-15=0

a = 13; b = 0; c = -15;
Δ = b2-4ac
Δ = 02-4·13·(-15)
Δ = 780
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{780}=\sqrt{4*195}=\sqrt{4}*\sqrt{195}=2\sqrt{195}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{195}}{2*13}=\frac{0-2\sqrt{195}}{26}
=-\frac{2\sqrt{195}}{26}
=-\frac{\sqrt{195}}{13}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{195}}{2*13}=\frac{0+2\sqrt{195}}{26}
=\frac{2\sqrt{195}}{26}
=\frac{\sqrt{195}}{13}
$