y=(1+3x)/(9-4x)

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Solution for y=(1+3x)/(9-4x) equation:


D( x )

9-(4*x) = 0

9-(4*x) = 0

9-(4*x) = 0

9-4*x = 0

9-4*x = 0 // - 9

-4*x = -9 // : -4

x = -9/(-4)

x = 9/4

x in (-oo:9/4) U (9/4:+oo)

y = (3*x+1)/(9-(4*x)) // - (3*x+1)/(9-(4*x))

y-((3*x+1)/(9-(4*x))) = 0

y-((3*x+1)/(9-4*x)) = 0

(-1*(3*x+1))/(9-4*x)+y = 0

(-1*(3*x+1))/(9-4*x)+(y*(9-4*x))/(9-4*x) = 0

y*(9-4*x)-1*(3*x+1) = 0

9*y-3*x-4*x*y-1 = 0

(9*y-3*x-4*x*y-1)/(9-4*x) = 0

(9*y-3*x-4*x*y-1)/(9-4*x) = 0 // * 9-4*x

9*y-3*x-4*x*y-1 = 0

9*y-4*x*y-1 = 0 // - 9*y-1

-4*x*y = -(9*y-1) // : -4*y

x = (-(9*y-1))/(-4*y)

x = (1-(9*y))/(-4*y)

x = (1-(9*y))/(-4*y)

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