y=(1/3)x-1;-2x+y=-6

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Remember to put linear equations with variables x and y.
for example:
2x+y=8
x+3y=14

Solution for y=(1/3)x-1;-2x+y=-6 system of equations: 


  • /| y-((1/3)*x)+1 = 0| y-2*x+6 = 0
  • We try to solve the equation: y-((1/3)*x)+1 = 0
  • y-1/3*x+1 = 0 // - 1-1/3*x
  • y = -(1-1/3*x)
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 6-2*x-(-1/3*x)-1 = 0| y = -(1-1/3*x)
  • 5-5/3*x = 0 // - 5
  • -5/3*x = -5 // : -5/3
  • x = -5/(-5/3)
  • x = 3
  • We insert the solution into one of the initial equations of our system of equations
  • For y = -(1-1/3*x): 
  • y = -(1-1/3*3)
  • y = -(1-1)
  • y = 0
  • We get a system of equations:
  • /| y = 0| x = 3

 

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