y=(1/x+2)+3

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Solution for y=(1/x+2)+3 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

y = 1/x+2+3 // - 1/x+2+3

y-(1/x)-3-2 = 0

y-x^-1-3-2 = 0

-1*x^-1 = -(y-5) // : -1

x^-1 = y-5

-1 < 0

1/(x^1) = y-5 // * x^1

1 = x^1*(y-5) // : y-5

1/(y-5) = x^1

x = 1/(y-5)

x = 1/(y-5)

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