y=(2x-1)/(x+1)

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Solution for y=(2x-1)/(x+1) equation: 


D( x )

x+1 = 0

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x in (-oo:-1) U (-1:+oo)

y = (2*x-1)/(x+1) // - (2*x-1)/(x+1)

y-((2*x-1)/(x+1)) = 0

(-1*(2*x-1))/(x+1)+y = 0

(-1*(2*x-1))/(x+1)+(y*(x+1))/(x+1) = 0

y*(x+1)-1*(2*x-1) = 0

x*y-2*x+y+1 = 0

(x*y-2*x+y+1)/(x+1) = 0

(x*y-2*x+y+1)/(x+1) = 0 // * x+1

x*y-2*x+y+1 = 0

x*y+y+1 = 0 // - y+1

x*y = -(y+1) // : y

x = (-(y+1))/y

x = -(y^-1*(y+1))

x = -(y^-1*(y+1))

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