y=(3y+1)/5

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Solution for y=(3y+1)/5 equation:



y=(3y+1)/5
We move all terms to the left:
y-((3y+1)/5)=0
We multiply all the terms by the denominator
y*5)-((3y+1)=0
Wy multiply elements
5y^2=0
a = 5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·5·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{10}=0$

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